Operations Management: Sustainability and Supply Chain Management 12th Edition by Jay Heizer Test ba
Answer:
(a) (2 lanes)(8 hours)(3600 seconds/hour)(1 checkout/45 seconds) = 1280 checkouts
(b) (4 lanes)(8 hours)(60 minutes/hour)(1 checkout/2 min) = 960 checkouts
(c) Cost for the old system = (4 workers)(8 hours)($10/hour) + ($0.10)(1280) + ($0.05)(1280) = $512. Cost for the new system = (1 worker)(8 hours)($10/hour) + ($0.15)(960) + ($0.05)(960) + $100 = $372. Multifactor productivity for old system = 1280 checkouts / $512 = 2.5 checkouts/$. Multifactor productivity for new system = 960 checkouts / $372 = 2.6 checkouts/$.
Diff: 3
Key Term: Multifactor productivity
AACSB: Analytical thinking
Objective: LO 1.5 Compute multifactor productivity
43) A swimming pool company has 100,000 labor hours available per summer and with a labor productivity of 5 pools per 6,000 hours.
a. How many pools can the company install this summer?
b. Suppose the multifactor productivity was one pool per $25,000. How much should the company expect to spend this summer constructing the pools?
Answer:
(a) 100,000 hours ∗ 5 pools/6000 hours = 83.33 or 83 pools
(b) 83 pools ∗ $25,000/pool = $2,075,000
Diff: 2
Key Term: Productivity
AACSB: Analytical thinking
Objective: LO 1.4 Compute single-factor productivity
44) An industrial plant needs to make 100,000 parts per month to meet demand. Each month contains 20 working days, each of which allows for 3 separate 8 hour shifts.
(a) If a worker can produce 10 parts/hour, how many workers are needed on each shift?
(b) If each shift has 100 workers, what is the productivity of an individual worker?
(c) If material costs are $10/part, capital costs are $100,000 and labor costs are $10/hour, what is the multifactor productivity of the plant from part (a)?
Answer:
(a) 100,000 parts × (1 hour / 10 parts) × (1 shift / 8 hours) × (1 worker/60 shifts) = 20.83 = 21 workers
(b) 100,000 parts / [(60 shifts/worker) × (100 workers) × (8 hours/shift)] = 2.08 parts/hour
(c) 100,000 parts / [($10/part) × (100,000 parts) + $100,000 + (21 workers) × (60 shifts/worker) × (8 hours/shift) × ($10/hour)] = .083 parts/$1
Diff: 2
Key Term: Productivity
AACSB: Analytical thinking
Objective: LO 1.5 Compute multifactor productivity
45) The local fast food store experienced the following number of customers on the night shift:
Hour----------------Customers
12 AM 23
1 AM 20
2 AM 15
3 AM 5
4 AM 2
5 AM 1
If the store was staffed by two workers, what was the average productivity per worker, in customers/hour?
Answer: (23 + 20 + 15 + 5 + 2 + 1) customers/ (2 workers ∗ 6 hours/worker) = 5.5 customers/hour
Diff: 2
Key Term: Productivity
AACSB: Analytical thinking
Objective: LO 1.4 Compute single-factor productivity
Section 9 Current Challenges in Operations Management
1) Current challenges in operations management include all of the following EXCEPT:
A) just-in-time performance.
B) rapid product development.
C) mass customization.
D) empowered employees.
E) None of the above are exceptions, i.e., all are current challenges.
Answer: E
Diff: 2
Key Term: Operations management
Objective: LO 1.1 Define operations management
Learning Outcome: Discuss operations and operations management as a competitive advantage for the organization
2) Which of the following statements about challenges in operations management is FALSE?
A) Job specialization is giving way to empowered employees.